{"id":201,"date":"2013-04-19T15:49:07","date_gmt":"2013-04-19T15:49:07","guid":{"rendered":"http:\/\/www.latinhire.com\/material\/?p=201"},"modified":"2014-06-28T07:27:07","modified_gmt":"2014-06-28T07:27:07","slug":"funciones-trigonometricas-tutoria-online-completa-con-estudiante","status":"publish","type":"post","link":"https:\/\/www.latinhire.com\/es\/funciones-trigonometricas-tutoria-online-completa-con-estudiante\/","title":{"rendered":"Funciones Trigonom\u00e9tricas: Tutor\u00eda Online completa con estudiante"},"content":{"rendered":"

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Comentarios del Tutor:<\/strong> Eleg\u00ed esta sesi\u00f3n dado que , a diferencia de la manera en que resolvemos este tipo de problemas en algunas partes de\u00a0Sudam\u00e9rica\u00a0, en EEUU optan por hacerlo utilizando esta \u00abregla\u00bb en lugar de emplear la identidad trigonom\u00e9trica Pitag\u00f3rica. Adem\u00e1s, se utilizan los recursos que se nos sugieren constantemente, chequeo de entendimiento. Un cierre de las sesi\u00f3n adecuado.<\/p>\n

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Student <\/strong>sec A = -4 , cot B =2\/3 with A in QII and B in QIII. Find: Sin 2A cos(A-B) tan B\/2 csc A\/2<\/p>\n

Tutor <\/strong>Welcome! How are you today?<\/p>\n

Student <\/strong>im ok. Frustrated<\/p>\n

Tutor <\/strong>oh, wellIll help you with this<\/p>\n

Student <\/strong>thank you!<\/p>\n

Tutor <\/strong>Any ideas about it?<\/p>\n

Student <\/strong>I know I will need to use a few different Identities. But im not sure how to find Sin andCos to make them work<\/p>\n

Tutor <\/strong>okay , first of all we need to get sin and cos for each angle
\nlet’s think about angle A<\/p>\n

Student <\/strong>yes , 1\/cos<\/p>\n

Tutor <\/strong>right, So how much is cos?<\/p>\n

Student <\/strong>-4x?<\/p>\n

Tutor <\/strong>we know sec is -4 and you told me sec is 1\/cos
\nso how much is cos?<\/p>\n

Student <\/strong>right<\/p>\n

Tutor <\/strong>if you have sec you flip it , and you get cos<\/p>\n

Student <\/strong>-1\/4<\/p>\n

Tutor <\/strong>perfect! Now we will use a triangle to get sin<\/p>\n

Student <\/strong>i cant believe I didnt get that<\/p>\n

Tutor <\/strong>we know cos is adj\/hyp right?<\/p>\n

Student <\/strong>yes<\/p>\n

Tutor <\/strong>so we place the 1 and the 4 , like this\u2026
\nHow can we get the missing side?<\/p>\n

Student <\/strong>then solve for b<\/p>\n

Tutor <\/strong>yes, how much is it?
\ngreat! So how much is sin?
\nperfect!<\/p>\n

Student <\/strong>where did the neg go from cos A<\/p>\n

Tutor <\/strong>\u00a0now we should work on angle B?
\nsec was negative and we also know the angle is in quad II is negative there<\/p>\n

Student <\/strong>\u00a0oh okay, but we dont nee that on the triangle?<\/p>\n

Tutor <\/strong>nope its the same<\/p>\n

Student <\/strong>oky<\/p>\n

Tutor <\/strong>just think about the quadrant<\/p>\n

Student <\/strong>ok<\/p>\n

Tutor <\/strong>what about B? Ideas?<\/p>\n

Student <\/strong>cot = cos\/sin<\/p>\n

Tutor <\/strong>right<\/p>\n

Student <\/strong>so would cos be 2 and sin be 3?<\/p>\n

Tutor <\/strong>[09:43] not exactly you should place the values in the triangle<\/p>\n

Student <\/strong>[09:54] ok<\/p>\n

Tutor <\/strong>and get the hypotenuse
\ngreat!
\nso , how much is sin B? and cos B?
\ncan we leave a root in the denominator?<\/p>\n

Student <\/strong>nope<\/p>\n

Tutor <\/strong>so?
\ngreat!
\nlet me tell you something angle B, Its in quadrant III, what do we know about the sin and cos values in q III?<\/p>\n

Student <\/strong>cos is neg \u00a0and so is sin<\/p>\n

Tutor <\/strong>[15:49] okay, so we place the neg sign for them, now we can get the asked values<\/p>\n

Student <\/strong>sin (A+A) is SinAcosA+CosAsinA<\/p>\n

Tutor <\/strong>okay , you can plug the values<\/p>\n

Student <\/strong>do i include teh negative here?<\/p>\n

Tutor <\/strong>yes! How much is that?<\/p>\n

Student <\/strong>do they cancel out?<\/p>\n

Tutor <\/strong>both are negative
\nhmmm, you cant do that , you must combine both then you can reduce<\/p>\n

Student <\/strong>oh!<\/p>\n

Tutor <\/strong>perfect!<\/p>\n

Student <\/strong>ok thx<\/p>\n

Tutor <\/strong>now let me tell you something we forgot about angle B<\/p>\n

Student <\/strong>ok<\/p>\n

Tutor <\/strong>its in quadrant III , so what do we know about sin and cos?<\/p>\n

Student<\/strong> cos is neg<\/p>\n

Tutor <\/strong>and sin?<\/p>\n

Student <\/strong>and so is sin<\/p>\n

Tutor <\/strong>so we place the neg sign for them<\/p>\n

Student <\/strong>i will try the others on my own and log back on if I cannot figure it out<\/p>\n

Tutor <\/strong>oh ok \u00a0great idea!<\/p>\n

Student <\/strong>thank you<\/p>\n

Tutor <\/strong>Thank you for using our service
\nPlease, do me the favour of completing the survey and comment before leaving<\/p>\n

Student <\/strong>yup<\/p>\n

Tutor <\/strong>Have a great day! Bye bye<\/p>\n

Student <\/strong>bye<\/p>\n

 <\/p>\n

Colaborador: Juan Belluscio, Tutor Argentino de Trigonometr\u00eda<\/strong><\/span><\/p>\n","protected":false},"excerpt":{"rendered":"

Comentarios del Tutor: Eleg\u00ed esta sesi\u00f3n dado que , a diferencia de la manera en que resolvemos este tipo de problemas en algunas partes de\u00a0Sudam\u00e9rica\u00a0, en EEUU optan por hacerlo utilizando esta \u00abregla\u00bb en lugar de emplear la identidad trigonom\u00e9trica Pitag\u00f3rica. Adem\u00e1s, se utilizan los recursos que se nos sugieren constantemente, chequeo de entendimiento. Un…<\/p>\n","protected":false},"author":9,"featured_media":3606,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"gallery","meta":{"footnotes":""},"categories":[89,88,86],"tags":[],"post_series":[],"class_list":["post-201","post","type-post","status-publish","format-gallery","has-post-thumbnail","hentry","category-ejemplos-de-tutorias","category-matematicas","category-trigonometria","post_format-post-format-gallery","entry","has-media"],"aioseo_notices":[],"aioseo_head":"\n\t\t\n\t\n\t\n\t\n\t\n\t\n\t\n\t\t\n\t\t\n\t\t\n\t\t\n\t\t\n\t\t\n\t\t\n\t\t\n\t\t\n\t\t\n\t\t\n\t\t